2.4x^2-4.5x+1.7=0

Solution for 2.4x^2-4.5x+1.7=0 equation:

2.4x^2-4.5x+1.7=0

a = 2.4; b = -4.5; c = +1.7;
Δ = b2-4ac
Δ = -4.52-4·2.4·1.7
Δ = 3.93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.5)-\sqrt{3.93}}{2*2.4}=\frac{4.5-\sqrt{3.93}}{4.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.5)+\sqrt{3.93}}{2*2.4}=\frac{4.5+\sqrt{3.93}}{4.8}
$